8x^2=28

Solution for 8x^2=28 equation:

8x^2=28

We move all terms to the left:

8x^2-(28)=0

a = 8; b = 0; c = -28;
Δ = b2-4ac
Δ = 02-4·8·(-28)
Δ = 896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{896}=\sqrt{64*14}=\sqrt{64}*\sqrt{14}=8\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{14}}{2*8}=\frac{0-8\sqrt{14}}{16}
=-\frac{8\sqrt{14}}{16}
=-\frac{\sqrt{14}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{14}}{2*8}=\frac{0+8\sqrt{14}}{16}
=\frac{8\sqrt{14}}{16}
=\frac{\sqrt{14}}{2}
$